Question

x²- 6x -16= 0
Qual a solução da equação

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-6x-16=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-6~e~c=-16\\\\\Delta=(b)^{2}-4(a)(c)=(-6)^{2}-4(1)(-16)=36-(-64)=100\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-6)-\sqrt{100}}{2(1)}=\frac{6-10}{2}=\frac{-4}{2}=-2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-6)+\sqrt{100}}{2(1)}=\frac{6+10}{2}=\frac{16}{2}=8\\\\S=\{-2,~8\}$