Question

Simplifique: a) √8 + √32 +√72-√50 =
b) √20 - √24 + √125 - √54 =
agradeço para quem responder essas duas

Answer 1

Oie, Td Bom?!

a)

$= \sqrt{8} + \sqrt{32} + \sqrt{72} - \sqrt{50}$

$= \sqrt{2 {}^{2} \: . \: 2 } + \sqrt{4 {}^{2} \: . \: 2} + \sqrt{6 {}^{2} \: . \: 2 } - \sqrt{5 {}^{2} \: . \: 2}$

$= \sqrt{2 {}^{2} } \sqrt{2} + \sqrt{4 {}^{2} } \sqrt{2} + \sqrt{6 {}^{2} } \sqrt{2} - \sqrt{5 {}^{2} } \sqrt{2}$

$= 2 \sqrt{2} + 4 \sqrt{2} + 6 \sqrt{2} - 5 \sqrt{2}$

$= (2 + 4 + 6 - 5) \sqrt{2}$

$= (12 - 5) \sqrt{5}$

$= 7 \sqrt{5}$

b)

$= \sqrt{20} - \sqrt{24} + \sqrt{125} - \sqrt{54}$

$= \sqrt{2 {}^{2} \: . \: 5} - \sqrt{2 {}^{2} \: . \: 6} + \sqrt{5 {}^{2} \: . \: 5} - \sqrt{3 {}^{2} \: . \: 6}$

$= \sqrt{2 {}^{2} } \sqrt{5} - \sqrt{2 {}^{2} } \sqrt{6} + \sqrt{5 {}^{2} } \sqrt{5} - \sqrt{3 {}^{2} } \sqrt{6}$

$= 2 \sqrt{5} - 2 \sqrt{6} + 5 \sqrt{5} - 3 \sqrt{6}$

$= (2 + 5) \sqrt{5} - ( - 2 - 3) \sqrt{6}$

$= 7 \sqrt{5} - 5 \sqrt{6}$

Att. Makaveli1996

Answer 2

Resposta:

a) = /8 + v32 + V72 V50 = v22 .2 + v42 . 2 + v62 . 2 - V52.2 = v2? /2+ V4?v2+ v6?/2 V5?V2 = 2/2 + 4v2 + 6/2 – 5/2 = (2+4+6 – 5) v2 = (12 – 5)/5 = 7/5

b) = v20 – V24 + v125 V54 = v22 .5 – V22.6+ v52.5 – V32 .6 = v2?/5 V2 V6 + v5? V5 – V32 6 = 2/5 2/6 + 5/5 – 3/6 %3D (2+5)v5 – (-2 – 3) v6 = 7/5 5V6