Question

considere a função definida por y=3x² - 2x -1

Answer 1

$3 x^{2}-2x-1=0$

Δ= $2^{2} -4.(-1).3$
Δ= $4+12$
Δ= $16$

$x=2 + \frac{ \sqrt{16} }{6}$
$x=2+ \frac{4}{6} \\ x= \frac{12}{6} + \frac{4}{6} \\ <strong>x= \frac{16}{6}$

$x=2- \frac{ \sqrt{16} }{6} \\ x=2- \frac{4}{6} \\ x= \frac{12}{6} - \frac{4}{6} \\<strong> x= \frac{8}{6}$