Question

Me ajudem, Não estou conseguindo resolver

Answer 1

Resposta:

$(\frac{1}{8} )^{x} = 16\\\\\frac{1}{8} = \sqrt[x]{16} \\\\8^{-1} = \sqrt[x]{16} \\\\8^{-x} = 16\\\\(2^{3} )^{-x} = 2^{4} \\\\2^{-3x} = 2^{4} \\\\-3x = 4\\\\x = - \frac{4}{3}$