Classifique, quanto á medida dos lados, o triângulo ABC nestes casos
a) A(1,1), B(2,3), C(5,-1)
b) A(1,1), B(0,2), C(2,-1)
c) A(-1,3), B(1,2), C(0,4)
Respostas
Resposta:
Explicação passo-a-passo:
a) A(1,1) e B(2,3)
dAB = √ (2-1)² + (3-1)²
dAB = √ (1)² + (2)²
dAB = √ 1+4
dAB = √ 5
dAB = 1,73
B(2,3) e C(5-1)
dBC = √ (5-2)² + (-1-3)²
dBC = √ (3)² + (-4)²
dBC = √ 9+16
dBC = √ 25
dBC = 5
dBC = 1,73
A(1,1) e C(5,-1)
dBC = √ (5-1)² + (-1-1)²
dBC = √ (4)² + (-2)²
dBC = √ 16 + 4
dBC = √ 20
dBC =4,47
B) A(1,1) e B(0,2)
dAB = √ (0-2)² + (1-1)²
dAB = √ (-2)² + (0)²
dAB = √ 2 + 0
dAB = √ 1,41
B(0,2) e C(2,1)
dBC = √ (2-0)² + (-1-1)²
dBC = √ (2)² + (-2)²
dBC = √ 4+4
dBC = √ 8
dBC = 2,82
A(1,1) e C(2,-1)
dBC = √ (2-1)² + (-1-1)²
dBC = √ (1)² + (-2)²
dBC = √ 1+4
dBC = 5
dBC = 2,23
C) A(-1,3) e B(1,2)
dAB = √ (3-1)² + (2,1)²
dAB = √ (2)² + (1)²
dAB = √ 2+1
dAB = √ 3
dAB = 1,73
B(1,2) e C(0,4)
dBC = √ (2-0)² + (4,1)²
dBC = √ (2)² + (3)²
dBC = √ 2+3
dBC = √ 5
dBC = 1,73
A(-1,3) e C(0,4)
dBC = √ (3-1)² + (-4-0)²
dBC = √ (2)² + (4)²
dBC = √ 2+4
dBC = √ 6
dBC = 2,44
Espero ter ajudado