• Matéria: Matemática
  • Autor: lukaslucas12345
  • Perguntado 9 anos atrás

Calcule o mmc de (8,10) (14,21) (50,25) (40,60) (80,56) e (6,8,10,12)
Por favor me ajudem!

Respostas

respondido por: enosmultibomsat
7
(8, 10) = 40
(14,21) = 42
(50,25) = 50
(40,60) = 120
(80,56) = 560
(6, 8 , 10, 12) = 120

enosmultibomsat: Espero ter aido útil
respondido por: emicosonia
12
Calcule o mmc de (8,10) (14,21) (50,25) (40,60) (80,56) e (6,8,10,12)
mmc(8,10)

8,10| 2
4, 5| 2
2, 5| 2
1,1/  
= 2x2x5
= 20
MMC(8,10) = 20

mmc(14,21)
14,21| 2
  7,21| 3
  7,  7| 7
  1,1/

= 2x3x7 
= 42
MMC(14,21) = 42

mmc(50,25)
50, 25| 2
25,25| 5
  5, 5| 5
   1,1/
=2x5x5
= 50

MMC(50,25) = 50

mmc(40,60)
40,60| 2
20,30| 2
10, 15| 2
  5,15| 3
  5,5 | 5
  1,1/

= 2x2x2x3x5 
=8x15
= 120
MMC(40,60) = 120

mmc(80,56)
80,56| 2
40,28| 2
20,14| 2
10,  7| 2
  5, 7| 5
  1, 7| 7
   1,1/
= 2x2x2x2x5x7
= 16x35
=  560
MMC(80,56) = 560

mmc(6,8,10,12)
6,8,10,12| 2
3,4, 5,  6| 2
3,2,5, 3| 2
3,1, 5, 3| 3
1,1,5,,1| 5
1,1,1,1/
= 2x2x2x3x5
= 8x15
= 120
MM(6,8,10,12) = 120

 
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