Question

uma reta passa pelo ponto p (- 1, -5) e tem coeficiente angular m= 1/2 escreva a equação da reta na forma reduzida

Answer 1

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$\Huge\green{\boxed{\rm~~~\gray{y}~\pink{=}~\blue{ \dfrac{x}{2} - \dfrac{9}{2} }~~~}}$

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$\bf\large\green{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad}}$

$\green{\rm\underline{EXPLICAC_{\!\!\!,}\tilde{A}O\ PASSO{-}A{-}PASSO\ \ \ }}$✍

❄☃ $\sf(\gray{+}~\red{cores}~\blue{com}~\pink{o}~\orange{App}~\green{Brainly})$ ☘☀

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☺lá, Chys, como tens passado nestes tempos de quarentena⁉ E os estudos à distância, como vão⁉ Espero que bem❗ Acompanhe a resolução abaixo, feita através de algumas manipulações algébricas, e após o resultado você encontrará um link com mais informações sobre Funções de Primeiro Grau que talvez te ajude com exercícios semelhantes no futuro. ✌

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☔ Inicialmente  temos que a equação da reta na forma reduzida é na forma

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$\Large\red{\boxed{\pink{\boxed{\begin{array}{rcl}&&\\&\orange{\sf y = a \cdot x + b}&\\&&\\\end{array}}}}}$

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$\pink{\Longrightarrow}~\Large\sf\orange{a}$ sendo o coeficiente angular da reta;

$\pink{\Longrightarrow}~\Large\sf\orange{b}$ sendo o coeficiente linear da reta.

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☔ Substituindo o ponto e o coeficiente angular na equação temos que

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➡ $\large\sf\blue{ -5 = \dfrac{1}{2} \cdot (-1) + b }$

➡ $\large\sf\blue{ -5 = \dfrac{-1}{2} + b }$

➡ $\large\sf\blue{ b = -5 + \dfrac{1}{2} }$

➡ $\large\sf\blue{ b = \dfrac{-9}{2} }$

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☔ O que nos revela a equação

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$\Huge\green{\boxed{\rm~~~\gray{y}~\pink{=}~\blue{ \dfrac{x}{2} - \dfrac{9}{2} }~~~}}$ ✅

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$\setlength{\unitlength}{0.95cm}\begin{picture}(6,5)\thicklines\put(0,0){\vector(1,0){5}}\put(0,0){\vector(0,1){5}}\put(0,0){\vector(-1,0){5}}\put(0,0){\vector(0,-1){5}}\put(5.3,0){x}\put(0.3,5){y}\put(-0.15,0.5){\_\_}\put(-0.15,1){\_\_}\put(-0.15,1.5){\_\_}\put(-0.15,2){\_\_}\put(-0.15,2.5){\_\_}\put(-0.15,3){\_\_}\put(-0.15,3.5){\_\_}\put(-0.15,4){\_\_}\put(-0.15,4.5){\_\_}\put(-0.15,-0.5){\_\_}\put(-0.15,-1){\_\_}\put(-0.15,-1.5){\_\_}\put(-0.15,-2){\_\_}\put(-0.15,-2.5){\_\_}\put(-0.15,-3){\_\_}\put(-0.15,-3.5){\_\_}\put(-0.15,-4){\_\_}\put(-0.15,-4.5){\_\_}\put(0.45,-0.08){ | }\put(0.95,-0.08){ | }\put(1.45,-0.08){ | }\put(1.95,-0.08){ | }\put(2.45,-0.08){ | }\put(2.95,-0.08){ | }\put(3.45,-0.08){ | }\put(3.95,-0.08){ | }\put(4.45,-0.08){ | }\put(-4.55,-0.08){ | }\put(-4.05,-0.08){ | }\put(-3.55,-0.08){ | }\put(-3.05,-0.08){ | }\put(-2.55,-0.08){ | }\put(-2.02,-0.08){ | }\put(-1.55,-0.08){ | }\put(-1.05,-0.08){ | }\put(-0.55,-0.08){ | }\put(-1.0,0.0){\circle*{0.13}}\put(-2.25,0.25){ \sf y = 0 }\put(0.0,1.0){\circle*{0.13}}\put(-1,1.25){ \sf x = 0 }\put(-5,-4){\line(1,1){9}}\end{picture}$

$\sf (Esta~imagem~n\tilde{a}o~\acute{e}~visualiz\acute{a}vel~pelo~App~Brainly$ ☹ )

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$\bf\large\red{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}$

✈  Funções de Primeiro Grau (https://brainly.com.br/tarefa/36220633)

$\bf\large\red{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad}}$✍

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$\bf\large\red{\underline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}$☁

☕ $\bf\Large\blue{Bons\ estudos.}$

($\large\orange{D\acute{u}vidas\ nos\ coment\acute{a}rios}$) ☄

$\bf\large\red{\underline{\qquad \qquad \qquad \qquad \qquad \qquad \quad }}\LaTeX$✍

❄☃ $\sf(\gray{+}~\red{cores}~\blue{com}~\pink{o}~\orange{App}~\green{Brainly})$ ☘☀

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$\gray{"Absque~sudore~et~labore~nullum~opus~perfectum~est."}$