Question

(UTFPR-2012) As raizes da equacao x²-4ax-4a²-b²=0 são:

Answer 1

a=1
b=-4a
c=(-4a²-b²)

Δ=b²-4ac
Δ=(-4a)²-4*1*(-4a²-b²)
Δ=16a²+16a²+4b²
Δ=32a²+4b²
Δ=4(8a²+b²)

x=-b±√Δ/2a
x=4a±√4(8a²+b²)/2*1
x=4a±2√8a²+b²/2

x'=4a+2√8a²+b²/2⇒=2a+√8a²+b²
x''=4a-2√8a²+b²/2⇒2a-√8a²+b²