Question

Resolva a seguinte equação exponencial​

Answer 1

Resposta:

$\huge\red {\boxed{ \bf{x = - 1}} }$

Explicação passo-a-passo:

$\mathsf{OI, TUDO \: \: J\acute{O}IA \: ? \: \:\blue {\heartsuit} }$

$\bf{ {2}^{x} + {2}^{x + 1} + {2}^{x + 2} + {2}^{x + 3} = \frac{15}{2} } \\ \bf{( 1 + 2 + {2}^{2} + {2}^{3} ) \times {2}^{x} = \frac{15}{2} } \\ \bf{(1 + 2 + 4 + 8) \times {2}^{x} = \frac{15}{2} } \\ \bf{15 \times {2}^{x} = \frac{15}{2} } \\ \bf{15 \times {2}^{x} \div 15 = \frac{15}{2} \div 15} \\ \bf{ {2}^{x} = \frac{15}{2} \times \frac{1}{15} } \\ \bf{ {2}^{x} = \frac{\cancel{15}}{2} \times \frac{1}{\cancel{15}} } \\ \bf{ {2}^{x} = \frac{1}{2} } \\ \bf{ {2}^{x} = {2}^{ - 1} } \\ \bf{ {\cancel{2}}^{x} = {\cancel{2}}^{ - 1} } \\ \red {\boxed{ \bf{x = - 1}}}$

$\mathcal{ATT : ARMANDO}$