Question

Resolva as seguintes equações.
5x + 10 = 50
x² = 64
3y – 10 = 20
z² +10 = 110

Answer 1

5x+10=50

5x=50-10

5x=40

$x = \frac{40}{5}$

x=8

${x}^{2} = 64 \\ x = \sqrt{64} \\ x = 8$

$3y - 10 = 20 \\ 3y = 20 + 10 \\ y = \frac{30}{3} \: \: \: y = 10$

${z}^{2} + 10 = 110 \\ {z}^{2} = 110 - 10 \\ z = \sqrt{100} \: \: \: \: z = 10$