• Matéria: Matemática
  • Autor: Mary287667
  • Perguntado 5 anos atrás


 \frac{4}{ \sqrt{5 + 1 \sqrt[4]{5 + 1 \sqrt[8]{5 + 1 \sqrt[16]{5 + 1} } } } }

Respostas

respondido por: xanddypedagogoowelwo
0

Resposta:

Vamos lá!

\dfrac{4}{\sqrt{5+1\sqrt[4]{5+1\sqrt[8]{5+1\sqrt[16]{5+1} } } } } =\\\\\\\dfrac{4}{\sqrt{5+1\sqrt[4]{5+1\sqrt[8]{5+1 [6^{\frac{1}{16}} ]  } } } } =\\\\\\\dfrac{4}{\sqrt{5+1\sqrt[4]{5+1[6^{\frac{1}{8} } .6^{\frac{1}{16}}  ] } } } } =\\\\\\\dfrac{4}{\sqrt{5+1[{6^{\frac{1}{4} }.6^{\frac{1}{8} } .6^{\frac{1}{16}}  ] } } } } =\\\\\\\dfrac{4}{{6^{\frac{1}{2} }.{6^{\frac{1}{4} }.6^{\frac{1}{8} } .6^{\frac{1}{16}}   } } } } =\\\\\\\dfrac{4}{{6^{\frac{8+4+2+1}{16} }} } }=\dfrac{4}{{6^{\frac{15}{16} }  } }=

\dfrac{4}{{\sqrt[16-14]{6^{15-14 } }  } }=\dfrac{4}{{\sqrt[2]{6^{1 } }  } }=\\\\\\\dfrac{4}{{\sqrt[]{6 }  } }*\sqrt{6} =\dfrac{4\sqrt{6} }{{\sqrt[]{36} }  } }=\\\\\\\dfrac{4\sqrt{6} }{{{6} }  } }=\dfrac{2\sqrt{6} }{3}

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