• Matéria: Matemática
  • Autor: mayslanroniel38
  • Perguntado 5 anos atrás

1. Determine o valor de xey para que se tenha A = B:
x + 4 11
-5 117
A
B =
9
9 13
2y+7
е
lo
13
(A) -9 e -10
(B) -9 e 3
(C) 1 e 10
(D) -9 e 10
(E) -2 e 6
7
1
2. Sendo A=
- 3
2
1
4
e BE
6)
determine 3A + 2B.
- 5
(A)
5 5
- 5 12
- 4
5 5
(B)
12
- 5 5 5
(C)
- 4 12
5 5
(D)
4 12
23 5
12
(E) -4
8
3. Sendo A=
6
-6
eB=
1
3
oleil
-3
8
determine A-B.
4 3
(A)
3 - 7
4 --9
(B
3 9
tmttt
5
4
(C)
3 12 .
4 -3
(D)
3 - 7
12 -9
(E)
9 9​

Anexos:

Respostas

respondido por: vitorjoaoaoao
4

Resposta:

1. (b)

2. (b)

3. (d)

Explicação passo a passo:

1)

Para isso, igualaremos os elementos que possuam as incógnitas x e y:

a_{11} = b_{11}\\x + 4 = -5\\x = -5 - 4\\x = -9 \\\\

----------------------

a_{22} = b_{22}\\2y+7 = 13\\2y = 13 - 7\\2y = 6\\y = \frac{6}{2}\\y = 3\\\\\\

2)

3\times\left[\begin{array}{cc}-3&1\\2&4\end{array}\right] + 2\times\left[\begin{array}{cc}7&1\\-5&0\end{array}\right]=\left[\begin{array}{cc}-9&3\\6&12\end{array}\right] + \left[\begin{array}{cc}14&2\\-10&0\end{array}\right]=  \left[\begin{array}{cc}5&5\\-4&12\end{array}\right]

3)

\left[\begin{array}{ccc}8&-6\\6&1\end{array}\right] - \left[\begin{array}{ccc}4&-3\\3&8\end{array}\right]= \left[\begin{array}{ccc}4&-3\\3&-7\end{array}\right]

Bons estudos e tenha um feliz Natal! ;)


mayslanroniel38: obrigado
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