Question

$log \frac{1}{9} \sqrt{27}$


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Answer 1

Utilizando as propriedades de logaritimos e de potencias temos temos

$\log_{\frac{1}{9}}\sqrt{27}=\log_{\frac{1}{3^2}}3^3=\log_{3^{-2}}3^3=\dfrac{-1}{2}\cdot 2\log_33=\dfrac{-1}{2}\cdot2=-1$