Question

use a suitable identity to get each of the following products (x+1)(x+1)​

Answer 1

Resposta:

$(x + 1)(x + 1)$

${x}^{2} + (1 + 1)x + 1.1$

${x}^{2} + x + x + 1$

${x}^{2} +2x + 1$

if you put the equals 0 to the equation, you can solve the bhaskara and find the zeros of the function.

NOTE:

(1 + 1) x

here, you can make a distributive (multiply the number outside by all inside the parentheses)

or you can add what you have inside the parentheses and after multiply the results by the number of outside.

Look..

(1 + 1)x (by distributive)

x . 1 + x. 1

x + x

2x

(1 + 1)x (by adding the numbers inside the parenteshes)

(2)x

(now solve this! multiply the number 2 by the x)

2 . x

2x

we'll have the same results

hope i help you