Question

alguém pode mim ajuda nessa equações de 2 grau não consegui resolver eu quero ajuda de vcs? vcs mim ajuda ?​

Answer 1

Resposta:

Boa tarde, Kledja! Tudo bem?

Explicação passo-a-passo:

Vamos lá! Utilize a fórmula da soma e do produto das raízes que facilitará sua resolução.

Então temos algumas respostas para lhe ajudar como exemplo:

$x^{2} -5x+6=0\\\\x'+x''=-\dfrac{b}{a} =5\\\\x'\cdot x''=\dfrac{c}{a}=6\\\\S=\{2,3\}\\\\\\\\x^{2} -8x+12=0\\\\x'+x''=-\dfrac{b}{a} =8\\\\x'\cdot x''=\dfrac{c}{a}=12\\\\S=\{2,6\}\\\\\\\\x^{2} +2x-8=0\\\\x'+x''=-\dfrac{b}{a} =-2\\\\x'\cdot x''=\dfrac{c}{a}=-8\\\\S=\{2,-4\}\\\\\\\\2x^{2} -8x+8=0\\\\x'+x''=-\dfrac{b}{a} =8/2=4\\\\x'\cdot x''=\dfrac{c}{a}=8/2=4\\\\S=\{2,2\}$

$x^{2} -4x-5=0\\\\x'+x''=-\dfrac{b}{a} =4\\\\x'\cdot x''=\dfrac{c}{a}=-5\\\\S=\{-1, 5\}\\\\\\\\-x^{2} +x+12=0\\\\x'+x''=-\dfrac{b}{a} =+1\\\\x'\cdot x''=\dfrac{c}{a}=-12\\\\S=\{-3, 4\}\\\\\\\\-x^{2} +6x-5=0\\\\x'+x''=-\dfrac{b}{a} =+6\\\\x'\cdot x''=\dfrac{c}{a}=+5\\\\S=\{1, 5\}\\\\\\\\3x^{2} -7x+2=0\\\\x'+x''=-\dfrac{b}{a} =7/3\\\\x'\cdot x''=\dfrac{c}{a}=2/3\\\\S=\{2, 1/3\}$

║Prof Alexandre║

Universidade de Pernambuco