• Matéria: Matemática
  • Autor: kennedy8676
  • Perguntado 5 anos atrás

qual o conjunto solução do sistema de inequacao {3x - 1 > 5x+ 2}
{ 4x+3 < 7x-11​

Respostas

respondido por: Gausss
0

S= Vazio

Explicação passo-a-passo:

S=\left\{ \begin{aligned} 3x - 1  &gt; 5x+ 2 \\ 4x+3  &lt;  7x-11\end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} 3x - 1   - 5x -  2  &gt; 0\\ 4x+3  - 7x + 11 &lt; 0\end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} - 2x -3 &gt; 0\\- 3x + 14 &lt; 0\end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} - 2x -3 &gt; 0 \:  \:  \times ( - 3)\\- 3x + 14 &lt; 0 \:  \:  \times (2)\end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} 6x  + 9  &lt;  0\\- 6x + 28&lt; 0\end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} 6x    &lt;   - 9\\- 6x &lt;  - 28\end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} x    &lt;    \frac{ - 9}{6} \\x &gt;  \frac{ - 28}{ - 6} \end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} x    &lt;     - \frac{ 3}{2} \\x &gt;  \frac{ 14}{ 3} \end{aligned} \right. \\  \\ S=\left\{ \begin{aligned} x    &lt;     -1,5\\x &gt; 4,6... \:  \end{aligned} \right. \\  \\  \boxed{\boxed{\underbrace{{S=\emptyset }}}}

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