Question

Me ajudem pliss é urgenteee

a) (-32abc): (+8ac)

b) (+40x⁷y²) : (-10x⁴y²)

c) (-100a³): (-25a³)

d) (+55a⁴bc²): (-11a²bc)​
Não precisa dos calculos

Answer 1

Para dividir monômios, divida os coeficientes, e subtraia os expoentes de letras iguais:

• (xaᵐb) : (yaⁿb) <=> (x:y)aᵐ⁻ⁿb¹⁻¹

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Letra A)

$\begin{array}{l}\sf (-32abc):(8ac)\\\\\sf (-32abc):(8ac)=\dfrac{-32abc}{8ac}\\\\\sf (-32abc):(8ac)=-4a^{1-1}bc^{1-1}\\\\\sf (-32abc):(8ac)=-4a^0bc^0\\\\\sf (-32abc):(8ac)=-4\cdot1\cdot b\cdot1\\\\\!\boxed{\sf (-32abc):(8ac)=-4b}\end{array}$

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Letra B)

$\begin{array}{l}\sf (40x^7y^2):(-10x^4y^2)\\\\\sf (40x^7y^2):(-10x^4y^2)=\dfrac{40x^7y^2}{-10x^4y^2}\\\\\sf (40x^7y^2):(-10x^4y^2)=-4x^{7-4}y^{2-2}\\\\\sf (40x^7y^2):(-10x^4y^2)=-4x^3y^0\\\\\sf (40x^7y^2):(-10x^4y^2)=-4x^3\cdot1\\\\\!\boxed{\sf (40x^7y^2):(-10x^4y^2)=-4x^3}\end{array}$

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Letra C)

$\begin{array}{l}\sf (-100a^3):(-25a^3)\\\\\sf (-100a^3):(-25a^3)=\dfrac{-100a^3}{-25a^3}\\\\\sf (-100a^3):(-25a^3)=4a^{3-3}\\\\\sf (-100a^3):(-25a^3)=4a^0\\\\\sf (-100a^3):(-25a^3)=4\cdot1\\\\\!\boxed{\sf (-100a^3):(-25a^3)=4}\end{array}$

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Letra D)

$\begin{array}{l}\sf (55a^4bc^2):(-11a^2bc)\\\\\sf (55a^4bc^2):(-11a^2bc)=\dfrac{55a^4bc^2}{-11a^2bc}\\\\\sf (55a^4bc^2):(-11a^2bc)=-5a^{4-2}b^{1-1}c^{2-1}\\\\\sf (55a^4bc^2):(-11a^2bc)=-5a^2b^0c^1\\\\\sf (55a^4bc^2):(-11a^2bc)=-5a^2\cdot1\cdot c\\\\\!\boxed{\sf (55a^4bc^2):(-11a^2bc)=-5a^2c}\end{array}$

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Att. Nasgovaskov