Question

log2 16 + log4 8+ log8 4 qual resposta?

Answer 1

$\log_2 16+\log_4 8+\log_8 4=$

$\frac{\log16}{\log2}+\frac{\log8}{\log4}+\frac{\log4}{\log8}=$

$\frac{\log2^4}{\log2}+\frac{\log2^3}{\log2^2}+\frac{\log2^2}{\log2^3}=$

$\frac{4\log2}{\log2}+\frac{3\log2}{2\log2}+\frac{2\log2}{3\log2}=$

$4+\frac{3}{2}+\frac{2}{3}=$

$\frac{24}{6}+\frac{9}{6}+\frac{4}{6}=$

$\frac{37}{6}$