Question

Preciso desse cálculo

Answer 1

$\frac{r}{6}-\frac{r-3}{4}=\frac{2r}{3}-1$

$\frac{2r}{12}-\frac{3r-9}{12}=\frac{8r}{12}-\frac{12}{12}$

$\frac{2r-(3r-9)}{12}=\frac{8r-12}{12}$

$2r-(3r-9)=8r-12$

$2r-3r+9=8r-12$

$2r-3r-8r=-12-9$

$-9r=-21$

$9r=21$

$r=\frac{21}{9}$

$r=\frac{7}{3}$