Question

alguem mim ajuda a determinar a resoluçao dessa equaçao X² - 6X + 5

Answer 1

$delta=b^2-4ac \\ -6^2-4*1*5 \\ 36-20 \\ delta =16 \\ \frac{-(-6)+- \sqrt{16} }{2*1} \\ \frac{6+- \sqrt{16} }{2} \\ x1= \frac{6+4}{2}=5 \\ x2= \frac{6-4}{2}=1$

Answer 2

DELTA =  36 - 20 = 16  OU v16 = +-4 *****

X = ( 6 +-4)/2
X1 = 10/2 = 5 ******
X2 = 2/2 = 1 *****