Question

Quais as raízes da equação 3x² + 4x + 1 = 0

URGENTE, ME AJUDEM PFV

Answer 1

S= -4

P = 3   -3 e -1

-3/3 = -1    -1/3

Resposta = -1 e -1/3

Answer 2

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~3x^{2}+4x+1=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=3{;}~b=4~e~c=1\\\\C\'alculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(4)^{2}-4(3)(1)=16-(12)=4\\\\C\'alculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(4)-\sqrt{4}}{2(3)}=\frac{-4-2}{6}=\frac{-6}{6}=-1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(4)+\sqrt{4}}{2(3)}=\frac{-4+2}{6}=\frac{-2}{6}=-\frac{1}{3}=\\S=\{-1,~-\frac{1}{3}\}$