Question

determine x nos casos​

Answer 1

a)

h²= m.n

x²= 4.9

x² = 36

x = √36

x = 4

b)

m.n =h²

x.(x+6) = 4²

x²+6x -36 = 0

∆= 6²-4.1.(36)=36 +144=180 => √180 = 6√5

x' = -b+√∆/2a = -6+6√5/2 = -3+3√5