Question

Supondo q log(√0,1) =x o valor de x² é​

Answer 1

$\log(\sqrt{0,1})=x$

$\log(0,1^{1/2})=x$

$\log[(10^{-1})^{1/2}]=x$

$\log(10^{-1/2})=x$

Por propriedade dos logaritmos, $\log(a^b)=b\cdot\log(a)$, logo:

$-\frac{1}{2}\cdot\log(10)=x$

Sendo $\log(10)=1$:

$-\frac{1}{2}=x$

$\frac{1}{4}=x^2$