• Matéria: Matemática
  • Autor: jrobertocruz6
  • Perguntado 5 anos atrás

28r+3r/2
14×2r/+3r/
7×2r=31r/2
15r/2

Respostas

respondido por: sakiba2zx
0

Resposta:

(2R,3R)-2-[7-[(2R,6R)-2,6-Dimethylmorpholin-4-yl]-7-oxoheptyl]-3-[(E,3R)-3-hydroxyoct-1-enyl]cyclopentan-1-one

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