Question

Me ajudem, com o calculo pfv​

Answer 1

B)

$(7-4)!=(3)!=3.2.1=6$

C)

$\displaystyle \frac{5!}{(3+2)!}=\frac{5!}{5!}=1$

E)

$3.4!+(3!-2)!+\sqrt{4!-8}=\\3.24+(6-2)!+\sqrt{24-8}=\\72+(4)!+\sqrt{16}=\\72+24+4=\\100$

J)

$\displaystyle \frac{P!}{(P-2)!}=\frac{P(P-1)!}{(P-2)!}=\frac{P(P-1)(P-2)!}{(P-2)!}=P(P-1)=P^2-P$