Question

Preciso de ajuda : ∫(2,1) 3/t^4dt

Answer 1

Explicação passo-a-passo:

$\sf{\int\limits^1_2 { \frac{3}{ {t}^{4} } } \, dt} \\ \\ \sf{\int\limits { \frac{3}{ {t}^{4} } } \, dt} \\ \\ \sf{3 \times \int\limits{ \frac{1}{ {t}^{4} } } \, dt} \\ \\ \sf{3 \times \left( - \frac{1}{(4 - 1) {t}^{4 - 1} } \right)} \\ \\ \sf{3 \times \left( - \frac{1}{ {3t}^{4 - 1} } \right)} \\ \\\sf{3 \times \left( - \frac{1}{ {3t}^{3} } \right)} \\ \\ \sf{ - 3 \times \frac{1}{ {3t}^{3} } } \\ \\ \sf{ - \frac{1}{ {t}^{3} } } \\ \\ \sf{ - \frac{1}{ {t}^{3} } \: \: |^1_2} \\ \\ \sf{ - \frac{1}{ {2}^{3} } -\left( - \frac{1}{ {1}^{3} } \right) } \\ \\ \sf{ - \frac{1}{8} -\left( - \frac{1}{ {1}^{3} } \right) } \\ \\ \sf{ - \frac{1}{8} - \left( - \frac{1}{1} \right)} \\ \\ \sf{ - \frac{1}{8} + \frac{1}{1} } \\ \\ \sf{ - \frac{1}{8} + 1} \\ \\ \boxed{\red{\mathsf{\boxed{\red{\mathsf{ \frac{7}{8} }}}}}}$

ATT:ARMANDO