• Matéria: Matemática
  • Autor: kimTaehy7
  • Perguntado 5 anos atrás

2. Calcule o m.m.c utilizando o 2º método (decomposição em fatores primos)


a) m.m.c (8,10)
b) m.m.c (12, 20)
c) m.m.c (7, 5)
d) m.m.c (8, 9)
e) m.m.c (60, 24)
f) m.m.c (18, 30)
g) m.m.c (3, 6, 9)
h) m.m.c (10, 12, 45)
i) m.m.c (6, 8, 12, 15)
j) m.m.c (12, 18, 36, 40)

Respostas

respondido por: matheusrickbatista
1

Resposta e explicação passo-a-passo:

a) m.m.c (8,10)

8, 10 | 2

4, 5 | 2

2, 5 | 2

1, 5 | 5

1, 1

2 x 2 x 2 x 5 = 40

b) m.m.c (12, 20)

12, 20 | 2

6, 10 | 2

3, 5 | 3

1, 5 | 5

1, 1

2 x 2 x 3 x 5 = 60

c) m.m.c (7, 5)

7, 5 | 5

7, 1 | 7

5 x 7 = 35

d) m.m.c (8, 9)

8, 9 | 2

4, 9 | 2

2, 9 | 2

1, 9 | 3

1, 3 | 3

1, 1

2 x 2 x 2 x 3 x 3 = 8 x 9 = 72

e) m.m.c (60, 24)

60, 24 | 2

30, 12 | 2

15, 6 | 2

15, 3 | 3

5, 3 | 3

5, 1 | 5

1, 1

2 x 2 x 2 x 3 x 3 x 5 = 8 x 9 x 5 = 72 x 5 = 360

f) m.m.c (18, 30)

18, 30 | 2

9, 15 | 3

3, 5 | 3

1, 5 | 5

1, 1

2 x 3 x 3 x 5 = 18 x 5 = 90

g) m.m.c (3, 6, 9)

3, 6, 9 | 2

3, 3, 9 | 3

1, 1, 3 | 3

1, 1, 1

2 x 3 x 3 = 18

h) m.m.c (10, 12, 45)

10, 12, 45 | 2

5, 6, 45 | 2

5, 3, 45 | 3

5, 1, 15 | 3

5, 1, 5 | 5

1, 1, 1

2 x 2 x 3 x 3 x 5 = 180

i) m.m.c (6, 8, 12, 15)

6, 8, 12, 15 | 2

3, 4, 6, 15 | 2

3, 2, 3, 15 | 2

3, 1, 3, 15 | 3

1, 1, 1, 5 | 5

1, 1, 1, 1

2 x 2 x 2 x 3 x 5 = 120

j) m.m.c (12, 18, 36, 40)

12, 18, 36, 40 | 2

6, 9, 18, 20 | 2

3, 9, 9, 10 | 2

3, 9, 9, 5 | 3

1, 3, 3, 5 | 3

1, 1, 1, 5 | 5

1, 1, 1, 1

2 x 2 x 2 x 3 x 3 x 5 = 360

Bons estudos.


kimTaehy7: Obrigada ;D
matheusrickbatista: por nada ^-^
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