• Matéria: Matemática
  • Autor: gpcosta619adr
  • Perguntado 5 anos atrás

1. Determine as potências.
a) 516' =

b) 40190 =
g) -104 =
c) 1 20 =
h) -(-7)3 =
i)

d) 0676 =
4
e) 107 =​

Anexos:

Respostas

respondido por: Anônimo
28

 \large{a)516 {}^{1} } =  \boxed {\red{516}}

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 \large {b)4019 {}^{0} } =  \boxed{ \red{ \: 1 \: }}

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 \large{c)1 {}^{20} } =  \boxed { \red{ \: 1 \: }}

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 \large{d)0 {}^{676}   =  \boxed{\red{ \: 0 \: }}}

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 \large{e)10 {}^{7}   } =

10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 =

 \large\boxed{ \red{10  \: 000 \: 000}}

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 \large{f)(  - \frac{2}{9} ) {}^{3} } =

 \large{ - ( \frac{2}{9} ) {}^{3} } =

 \large{ \frac{2 {}^{3} }{9 {}^{3} } } =

 \large\boxed{ \red{ \frac{8}{729} }}

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 \large{g) - 10 {}^{4} } =

 \large{ - (10 \times 10 \times 10 \times 10)} =

 \large\boxed{  \red{ - 10  \: 000}}

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 \large{h) - ( - 7) {}^{3} } =

 \large{( - 7) {}^{3}}  =

 \large{ - (7  \times 7 \times 7)} =

 \large\boxed{ \red{ - 343}}

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 \large{i)( -  \frac{1}{4} ) {}^{2} } =

 \large{( \frac{1}{4} ) {}^{2} } =

 \large{ \frac{1 {}^{2} }{4 {}^{2} } } =

 \large\boxed{ \red{ \frac{1}{16} }}

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Att, IzabelaCristina2006 ❤️ ♈

respondido por: mariac19godoy
3

A) 516'= 516

B)4019'0= 1

C)1'20= 1

D)0'676= 0

E)10'7= 10.000.000

F)(-2/9)'3= 8/7

G)-10'4= 10.000

H)-(-7)'3= -343

I) (-1/4)'2= 1/16

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