Question

encontre as raízes da equação do segundo grau no conjunto dos números reais x²+5x+6=0​

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+5x+6=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=5~e~c=6\\\\C\'alculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(5)^{2}-4(1)(6)=25-(24)=1\\\\C\'alculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(5)-\sqrt{1}}{2(1)}=\frac{-5-1}{2}=\frac{-6}{2}=-3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(5)+\sqrt{1}}{2(1)}=\frac{-5+1}{2}=\frac{-4}{2}=-2\\\\S=\{-3,~-2\}$