Question

ALGUÉM SABEEEEE????​

Answer 1

a)  $2^{3x} ^{+1} < 2\\2^{3x} ^{+1} < 2^{1} \\3x + 1 < 1\\3x < 0\\x < 0$

b) ≥$\frac{1}{2} \geq 8 ^{x}^{+ 2} \\2^{-x-1} \geq 2^{3x+6} \\-x-1 \geq 3x + 6\\-x-3x \geq 6 + 1\\-4x \geq 7\\x \leq \frac{-7}{-4}$

Answer 2

Resposta

Explicação passo-a-passo:

$2^{3x+1} <2^{1}$

corta a base 2 temos

$3x+1<1\\3x<1-1\\x<0$

$(\frac{1}{2} )^{x+1} \geq 8x^{x+2} \\2^{-x-1} \geq 2^{3.(x+2)}$

corta a base 2

$-x-1\geq 3x+6\\-x-3x\geq 6+1\\-4x\geq 7 .(-1)\\4x\leq -7\\x\leq \frac{-7}{4}$