Question

ajuda com essa questão

Answer 1

A=[4y..2 9..x²+4]
B=[12..2 9....53]

Agora é só comparar.

4y=12
y=12/4
y=3

x²+4=53
x²=53-4
x²=49
x=√49
x=7

Answer 2

$A = \left[\begin{array}{ccc}4y&2\\9 & x^{2} + 4 \\\end{array}\right] B = \left[\begin{array}{ccc}12&2\\9&53\\\end{array}\right] \\ \\ 4y = 12 \\ y = \frac{12}{4} \\ \boxed{y = 3} \\ \\ x ^{2} + 4 = 53 \\ x^{2} = 53 - 4 \\ x^{2} = 49 \\ x = \sqrt{49} \\ \boxed{x = 7}$