A) [(1/2+1/3)+1/4-(1-5/8)]+2/3
B) (1/3*3/5+10/7*7/5)/(2-1/2*3/4)
C) [(3/5)^2 / 27/25] / 1/6
Por favor estou com dificuldade nessas
Respostas
Resposta:
\left\{\left(\dfrac{1}{2}+\dfrac{1}{3} \right )+\dfrac{1}{4}-\left(1-\dfrac{5}{8} \right ) \right \}+\dfrac{2}{3}{(
2
1
+
3
1
)+
4
1
−(1−
8
5
)}+
3
2
Resolvemos as expressões dos parênteses primeiro. Como estamos operando com frações de denominadores diferentes, devemos tirar o m.m.c. dos denominadores:
\begin{gathered}\left\{\left(\dfrac{1}{2}+\dfrac{1}{3} \right )+\dfrac{1}{4}-\left(1-\dfrac{5}{8} \right ) \right \}+\dfrac{2}{3}\\ \\ =\left\{\left(\dfrac{6\div2 \times 1}{6}+\dfrac{6 \div 3 \times 1}{6} \right )+\dfrac{1}{4}-\left(\dfrac{8}{8}-\dfrac{5}{8} \right ) \right \}+\dfrac{2}{3}\\ \\ =\left\{\left(\dfrac{3 \times 1}{6}+\dfrac{2 \times 1}{6} \right )+\dfrac{1}{4}-\left(\dfrac{8-5}{8} \right ) \right \}+\dfrac{2}{3}\\ \\ =\left\{\left(\dfrac{3}{6}+\dfrac{2}{6} \right )+\dfrac{1}{4}-\left(\dfrac{3}{8} \right ) \right \}+\dfrac{2}{3}\\ \\ =\left\{\left(\dfrac{3+2}{6} \right )+\dfrac{1}{4}-\dfrac{3}{8} \right \}+\dfrac{2}{3}\\ \\ =\left\{\dfrac{5}{6}+\dfrac{1}{4}-\dfrac{3}{8} \right \}+\dfrac{2}{3}\\ \\ =\left\{\dfrac{24 \div 6 \times 5}{24}+\dfrac{24 \div 4 \times 1}{24}-\dfrac{24 \div 8 \times 3}{24} \right \}+\dfrac{2}{3}\\ \\ =\left\{\dfrac{4 \times 5}{24}+\dfrac{6 \times 1}{24}-\dfrac{3 \times 3}{24} \right \}+\dfrac{2}{3}\\ \\\end{gathered}
{(
2
1
+
3
1
)+
4
1
−(1−
8
5
)}+
3
2
={(
6
6÷2×1
+
6
6÷3×1
)+
4
1
−(
8
8
−
8
5
)}+
3
2
={(
6
3×1
+
6
2×1
)+
4
1
−(
8
8−5
)}+
3
2
={(
6
3
+
6
2
)+
4
1
−(
8
3
)}+
3
2
={(
6
3+2
)+
4
1
−
8
3
}+
3
2
={
6
5
+
4
1
−
8
3
}+
3
2
={
24
24÷6×5
+
24
24÷4×1
−
24
24÷8×3
}+
3
2
={
24
4×5
+
24
6×1
−
24
3×3
}+
3
2
\begin{gathered}=\left\{\dfrac{4 \times 5}{24}+\dfrac{6 \times 1}{24}-\dfrac{3 \times 3}{24} \right \}+\dfrac{2}{3}\\ \\ =\left\{\dfrac{20}{24}+\dfrac{6}{24}-\dfrac{9}{24} \right \}+\dfrac{2}{3}\\ \\ =\left\{\dfrac{20+6-9}{24} \right \}+\dfrac{2}{3}\\ \\ =\dfrac{17}{24}+\dfrac{2}{3}\\ \\ =\dfrac{17}{24}+\dfrac{24 \div 3 \times 2}{24}\\ \\ =\dfrac{17}{24}+\dfrac{8 \times 2}{24}\\ \\ =\dfrac{17}{24}+\dfrac{16}{24}\\ \\ =\dfrac{17+16}{24}\\ \\ =\dfrac{33}{24}\\ \\ =\dfrac{33 \div 3}{24 \div 3}\\ \\ =\dfrac{11}{8}\end{gathered}
={
24
4×5
+
24
6×1
−
24
3×3
}+
3
2
={
24
20
+
24
6
−
24
9
}+
3
2
={
24
20+6−9
}+
3
2
=
24
17
+
3
2
=
24
17
+
24
24÷3×2
=
24
17
+
24
8×2
=
24
17
+
24
16
=
24
17+16
=
24
33
=
24÷3
33÷3
=
8
11
Resposta: precisara resumir isso mas respondo pelos comentarios ok !!!!
Explicação passo-a-passo: