Question

EXERCÍCIO: RACIONALIZE AS FRAÇÕES ABAIXO.​

Answer 1

Olá!

Vamos calcular:

a) $\frac{7}{\sqrt{3} }$ =

$\frac{7.\sqrt{3}}{\sqrt{3}.\sqrt{3} }$ =

$\frac{7\sqrt{3} }{(\sqrt{3} )^{2} }$ =

$\frac{7\sqrt{3}}{3}$

b) $\frac{2}{\sqrt{3}+\sqrt{7}}$ =

$\frac{2(\sqrt{3}-\sqrt{7})}{(\sqrt{3}+\sqrt{7})(\sqrt{3}-\sqrt{7})}$ =

$\frac{2(\sqrt{3}+\sqrt{7})}{(\sqrt{3}+\sqr{7})(\sqrt{3}-\sqr{7})}$ =

$\frac{2(\sqrt{3}-\sqrt{7})}{(\sqrt{3})^{2}-(\sqrt{7})^{2}}$ =

$\frac{2(\sqrt{3}-\sqrt{7})}{3-7}$ =

\frac{2(\sqrt{3}-\sqrt{7})}{-4} =

-\frac{2(\sqrt{3}-\sqrt{7})}{4}

c) $\frac{3}{\sqrt{5} }$ =

$\frac{3.\sqrt{5}}{\sqrt{5}.\sqrt{5} }$ =

$\frac{3\sqrt{5} }{(\sqrt{5} )^{2} }$ =

$\frac{3\sqrt{5}}{5}$

d) $\frac{e}{\sqrt[3]{a} }$ =

$\frac{e.\sqrt[3]{a} }{\sqrt[3]{a}.\sqrt[3]{a}}$ =

$\frac{e\sqrt[3]{a} }{(\sqrt[3]{a} )^{2} }$ =

$\frac{e\sqrt[3]{a}}{\sqrt[3]{a^{2} } }$ =

$\frac{e\sqrt[3]{a}}{a^{\frac{2}{3} } }$

Abraços!