Question

Me ajudem por favor!!!!
A) (x−3)2+3x(x+1)−x=33

Answer 1

Resposta:

3 e -13/3

Explicação passo-a-passo:

(x - 3)*2 + 3x(x + 1) - x = 33

2x - 6 + 3x² + 3x - x = 33

3x² + 4x - 39 = 0

Δ = b² - 4ac

Δ = 16 - 4(3*-39)

Δ = 16 + 468 = 484

x = (-b +- \|Δ)/2a

x = (-4 +- 22)/6

x1 = (-4 + 22)/6 = 18/6 = 3

x2 = (-4 - 22)/6 = -26/6 = -13/3

\| = raiz quadrada, desculpa se ficou confuso.

Answer 2

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$\boxed{\begin{array}{l}\rm a)\\\sf(x-3)^2+3x\cdot(x+1)-x=33\\\sf x^2-6x+9+3x^2+3x-x=33\\\sf 4x^2-6x+3x-x+9-33=0\\\sf 4x^2-4x-24=0\div4\\\sf x^2-x-6=0\\\sf\Delta=b^2-4ac\\\sf\Delta=(-1)^2-4\cdot1\cdot(-6)\\\sf\Delta=1+25\\\sf\Delta=25\\\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\sf x=\dfrac{-(-1)\pm\sqrt{25}}{2\cdot1}\\\sf x=\dfrac{1\pm5}{2}\begin{cases}\sf x_1=\dfrac{1+5}{2}=\dfrac{6}{2}=3\\\sf x_2=\dfrac{1-5}{2}=-\dfrac{4}{2}=-2\end{cases}\\\huge\boxed{\boxed{\boxed{\boxed{\sf S=\{-2,3\}}}}}\end{array}}$