Question

gente me ajuda a responder essa questões tenho que entregar hoje se não fico de recuperação

Answer 1

 Aplicando as relações pertinentes

AREA LATERAL = AL
           AL = 6x([1x90)
                                           AL = 540 cm^2

AREA TOTAL = AT
          AT = 2x(área base) + AL
                                                     área base (área pentágono) = Ab
                                                   Ab = 3(L^2√3)/2
                                                              L = lado
                                                   Ab = 3(1^1x√3)/2
                                                   Ab = 2,55 
         AT = 2(2,55) + 540                
                                                         AT = 545,1 cm^2

VOLUME = V
          V = Ab x altura
             = 2,55 x 90
                                                  V = 229,5 cm^3

Answer 2

Sólido de base hexagonal, portanto 6 área laterais iguais:

$A_L = 6 (1 \times 90) \to~~ A_L = 6 \times 90 \to~~ \large\boxed{ A_L = 540 ~cm^2}$




$A_B= \dfrac{ 3\times l^2 \sqrt{3} }{2} \to~~A_B= \dfrac{ 3\times 1^2 \times \sqrt{3} }{2} \to~~ A_B= \dfrac{ 3\times 1\sqrt{3} }{2} \to\\\\ A_B= \dfrac{3\sqrt{3}}{2}}~ cm^2 \\\\\\ Sendo: \sqrt{3} \approx 1,7\\\\ A_B= \dfrac{3\times 1,7}{2}\to~~ A_B= \dfrac{5,1}{2}\to~~ \boxed{A_B\approx 2,55~cm^2}$



$A_T=A_L+2\timesA_B\to~~ A_T=540+2\times 2,55\to~~ A_T=540+5,1\to\\\\ \large\boxed{A_T=545,1~cm^2}$




$V=A_B\times H\to~~ V = 2,55 \times 90\to~~ \large\boxed{V=229,5~cm^3}$