Question

a) preencha o quadro Tempo x Altura e esboce o gráfico da função no plano cartesiano ​

Answer 1

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⠀⠀☞ Com os pares ordenados do quadro preenchido pudemos esboçar o gráfico no plano cartesiano. ✅

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⠀⠀ Vamos inicialmente completar o quadro tempo X altura assumindo que o tempo é nossa variável independente (eixo x) e a altura a nossa  variável dependente (eixo y):

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$\blue{\sf~~\begin{cases}\sf~x = 0~~\longrightarrow~~y = -5 \cdot 0^2 + 20 \cdot 0 = 0\\\\ \sf~x = 1~~\longrightarrow~~y = -5 \cdot 1^2 + 20 \cdot 1 = 15\\\\ \sf~x = 2~~\longrightarrow~~y = -5 \cdot 2^2 + 20 \cdot 2 = 20\\\\ \sf~x = 3~~\longrightarrow~~y = -5 \cdot 3^2 + 20 \cdot 3 = 15\\\\ \sf~x = 4~~\longrightarrow~~y = -5 \cdot 4^2 + 20 \cdot 4 = 0\end{cases}}$

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$\Large\green{\boxed{\rm\blue{\begin{array}{c|c}\underline{\sf t(s)}&\underline{\sf h(m)}\\&\\0&0\\&\\1&15\\&\\2&20\\&\\3&15\\&\\4&0\\\end{array}}}}$

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$\setlength{\unitlength}{0.95cm}\begin{picture}(6,5)\thicklines\put(0,0){\vector(1,0){5}}\put(0,0){\vector(0,1){5}}\put(4.8,0.2){x}\put(0.2,4.8){y}\put(0.0,0.0){\circle*{0.13}}\put(0.82,3.0){\circle*{0.13}}\put(1.50,3.75){\circle*{0.13}}\put(2.18,3.0){\circle*{0.13}}\put(3.0,0.0){\circle*{0.13}}\bezier(0,0)(1.5,7.5)(3,0)\end{picture}$

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$\footnotesize\sf (Esta~imagem~n\tilde{a}o~\acute{e}~visualiz\acute{a}vel~pelo~App~Brainly$ ☹ )  

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⠀⠀Como esperado, uma parábola de abertura voltada para baixo (pois a < 0) e que passa pela origem (pois c = 0). ✌

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$\bf\large\red{\underline{\quad\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}$

⠀⠀☀️ Leia mais sobre funções de segundo grau:

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✈ https://brainly.com.br/tarefa/38050217  

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⠀⠀⠀⠀☕ $\Large\blue{\text{\bf Bons~estudos.}}$

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