Question

racionalize
$\frac{3}{2 - \sqrt{6} }$
​

Answer 1

Resposta:

$\frac{3}{2-\sqrt{6} } . \frac{2+\sqrt{6} }{2+\sqrt{6} } \\\\\\\frac{3 (2+\sqrt{6}) }{(2-\sqrt{6} ).(2+\sqrt{6})}\\\\\frac{3(2+\sqrt{6} )}{2^{2} - \sqrt{6}^{2} } \\\\\frac{3(2+\sqrt{6} )}{4 - 6 } \\\\\frac{3(2+\sqrt{6} )}{-2 }$