Question

me ajudem e para segunda​

Answer 1

Olá!

a) $(\sqrt{11} )^{2}$ =

$\sqrt{11^{2} }$ =

$11^{2:2}$ =

11

b) $(\sqrt[3]{a} )^{4}$ =

$\sqrt[3]{a^{4} }$ =

$a^{\frac{4}{3} }$

c) $(5\sqrt{6} )^{2}$ =

5² · $\sqrt{6^{2} }$ =

25 · $6^{\frac{2}{2} }$ =

25 · 6 =

150

d) $(6\sqrt{a} )^{2}$ =

6² · $(\sqrt{a} )^{2}$ =

36 · $a^{\frac{2}{2} }$ =

36a

e) $(2\sqrt{3x-1} )^{2}[/tex = </p><p>2² · [tex](\sqrt{3x-1} )^{2}$ =

4 · $(3x-1)^{\frac{2}{2} }$ =

4(3x-1) =

12x - 4

f) $(\frac{a}{b}\sqrt{a} )^{2}$ =

$(\frac{a}{b} )^{2}$ · $(\sqrt{a} )^{2}$ =

$\frac{a^{2} }{b^{2} }$ · $a^{\frac{2}{2} }$ =

$a\frac{a^{2} }{b^{2} }$ =

$\frac{a^{3} }{b^{2}}$

g) $(\frac{a}{2}\sqrt{\frac{2}{ab} } )^{2}$ =

$\frac{a^{2} }{2^{2}}$ · $(\frac{2}{ab} )^{\frac{2}{2} }$ =

$\frac{a^{2}}{4}$ · $\frac{2}{ab}$ =

$\frac{2a^{2} }{4ab}$ =

$\frac{a^{2} }{2ab}$

Abraços!