Question

Qual o valor da soma : S=Log(base10) 0,001+ Log(base 3) 3(raiz quadrada) 3 - Log(base8) 16?

Answer 1

S = log10 0,001 + log3 3raiz3 - log8 16
S= log10 10^(-3) + log3 3 * 3^(1/2) - log8 2 * 8
S = - 3log10 10 + log3 3^(3/2) - 2log8 8
S = - (3 * 1) + 3/2log3 3 -  (2 * 1)
S = - 3 + (3/2 * 1) - 2
S = - 3 +3/2 - 2
S = (- 6 + 3 - 4) / 2
S = - 7/2