Question

Calcule a Massa Molecular (M.M.) dos seguintes reagentes: Hidróxido de Sódio (NaOH), Ácido Sulfúrico (H2SO4) , Sacarose (C12H22O11), Sulfato de Cobre Pentahidratado (CuSO4 . 5 H2O), Sulfato de Cobre Anidro (CuSO4) e Fosfato de Cálcio (Ca3(PO4)2. Dados de Massas Atômicas: Na = 23 u, O = 16u, H = 1 u, S = 32 u, C = 12u, Cu = 63,5 u, Ca = 40 u, P = 31 u. Lembrando que 1 mol equivale a 1 unidade de massa molecular do reagente. Assinale a alternativa correta na sequência apresentada. *

A) 40 g/mol, 98 g/mol, 342 g/mol, 249,5 g/mol, 159,5 g/mol e 310 g/mol.

B) 57 g/mol, 98 g/mol, 342 g/mol, 249,5 g/mol, 249 g/mol e 246 g/mol.

C) 40 g/mol, 99 g/mol, 342 g/mol, 240 g/mol, 159,5 g/mol e 310 g/mol.

D) 23 g/mol, 49 g/mol,171 g/mol, 250 g/mol, 160 g/mol e 246 g/mol.

E) 23 g/mol, 49 g/mol, 171 g/mol, 250 g/mol, 160 g/mol e 310 g/mol.​

Answer 1

Resposta:A) 40 g/mol, 98 g/mol, 342 g/mol, 249,5 g/mol, 159,5 g/mol e 310 g/mol.

Explicação:

NaOH--->23.1+16.1+1.1--->23+16+1--->40 g/mol

H2SO4--->1.2+32.1+16.4--->2+32+64--->98 g/mol

C12H22O11--->12.12+1.22+16.11--->144+22+176--->342 g/mol

CuSO4.5H2O--->63,5.1+32.1+16.4+5.(1.2+16.1)--->63,5+32+64+5.(2+16)--->159,5+5.18--->159,5+90--->249,5 g/mol

CuSO4--->63,5.1+32.1+16.4--->63,5+32+64--->159,5 g/mol

Ca3(PO4)2--->40.3+31.2+16.8--->120+62+128--->310 g/mol

CuSO4.5H2O--->64.1+32.1+16.4+5.(1.2+16.1)--->64+32+64+5.(2+16)--->160+5.18--->160+90--->250 g/mol

CuSO4--->64.1+32.1+16.4--->64+32+64--->160 g/mol