Question

2p ² - 4pq - 3q² para p= 1/6 e q= 2/3​

Answer 1

Resposta:

2.(1/6)² - 4.1/6.2/3 - 3.(2/3)² =

2.1/36 - 4/9 - 3.4/9 =

1/18 - 4/9 - 4/3 =

1/18 - 8/18 - 24/18 =

- 31/18 = - 1 13/18

Explicação passo-a-passo:

Answer 2

• Temos:

P=1/6  Q=2/3

Fazemos a resolução:

$\boxed{\begin{array}{lr} \large \sf 2\times\left(\dfrac{1}{6}\right)^{2}-4\times\dfrac{1}{\diagup\!\!\!\!6}\times\dfrac{\diagup\!\!\!\!2}{3}-3\times\left(\dfrac{2}{3}\right)^{2} \\ \\ \large \sf \diagup\!\!\!\!2\times\dfrac{1}{\diagup\!\!\!\!\!36}-4\times\dfrac{1}{3}\times\dfrac{1}{3}-\diagup\!\!\!\!3\times\dfrac{4}{\diagup\!\!\!\!9}\\ \\ \large \sf \dfrac{1}{18}-\dfrac{4}{9}-\dfrac{4}{3}\to mmc\:18{,}9{,}3=18 \\ \\ \large \sf \dfrac{1-8-24}{18} \\ \\ \large \sf \dfrac{-31}{18} \end{array}}$

• Logo fazemos a formula para inverter o sinal negativo:

$\large\boxed{\boxed{\sf \dfrac{-a}{b}=\dfrac{a}{-b}=-\dfrac{a}{b}}}$

Aplicamos a formula:

$\boxed{\boxed{\sf \dfrac{-31}{18}=\dfrac{31}{-18}=-\dfrac{31}{18}}}$

Logo a resposta será:

$\boxed{\boxed{\sf -\dfrac{31}{18}}}\Longleftarrow$

Bons  estudos =)