Question

qual e o vertice da parabola y= x²+6x-5

Answer 1

delta= (b)²-4.a.c
delta= (6)²-4.1.-5
delta= 36+20
delta=raíz de 56
x= -b+/- raisdedelta/2.a
x= -6+/-7,48/2
x'= -6+7,48/2= 1,78/2= x'= 0,74
x"= -6-7,48/2= -13,48/2= x"= -6,74

vertice=(-b/2.a;-delta/4.a)
vertice=(-6/2;-56/4)
vertice=(-3;-14)

Answer 2

Resposta:

delta= (b)²-4.a.c

delta= (6)²-4.1.-5

delta= 36+20

delta=raíz de 56

x= -b+/- raisdedelta/2.a

x= -6+/-7,48/2

x'= -6+7,48/2= 1,78/2= x'= 0,74

x"= -6-7,48/2= -13,48/2= x"= -6,74

vertice=(-b/2.a;-delta/4.a)

vertice=(-6/2;-56/4)

vertice=(-3;-14)