Question

Sabendo que log 11 na base 6 = 1,34 e log de 2 na base 6 = 0,37, calcule: log de 44 na base 6 e log de 121/8 na base 6.

Answer 1

$log_{6} 44= log_{6}(4.11)= log_{6}4+ log_{6}11= log_{6} 2^{2} + 1,34=2 log_{6}2 +1,34 \\ =2.0,37+1,34=0,74+1,34=2,08$

$log_{6} (\frac{121}{8})= log_{6}( \frac{ 11^{2} }{ 2^{3} })= log_{6} 11^{2} - log_{6} 2^{3} = \\ 2 log_{6}11-3 log_{6}2=2.1,34-3.0,37=2,68-1,11=1,57$