• Matéria: Matemática
  • Autor: lorraynedias1
  • Perguntado 9 anos atrás

3x²-2x-8=0 como faço essa equação

Respostas

respondido por: thiaguinhomucur
56
Delta=b²-4.a.c
delta=4-4.3.(-8)
delta=100

x=2+-10/6
x1=2
x2=-8/6

thiaguinhomucur: dlta=b²-4.a.c
delta=4-4.3.(-8)
delta=100
X=-b+-raiz de 100/2.a
X=2+-10/6
X1=2
X2=-8/6
respondido por: india2015
32


formula de baskara               Δ=b²-4ac                                   x=-b+ √Δ/2a

a=3                                        Δ=(-2)²-4(3)(-8)                         x=[-(-2)+√100]/2(3)

b=-2                                       Δ=4+96                                     x=[2 +10]/6=2

c=-8                                       Δ=100                                       x=[2-10]/6= -8/6=-2/3

 resposta : x=  2 e -2/3

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