Question

2- Considerando-se log10 2= 0,30 e log10 3=47 determinei log10 60
A)1,77
B)0,77
C)1,87
D)1,97
E)2,07

Answer 1

log 60

log (2.3.10)

log2 + log3 + log10

0,30 + 0,47 + 1

A) 1,77