Question

a) 50 °na escala celcius


F na escala Celsius

b) - 40 oC na escala Fahrenheit

c) 393 K na escala Celsius

d) 30 oC na escala Kelv​

Answer 1

Resposta:

a) 50° F  → °C  ⇒ $\frac{TC}{5} = \frac{TF-32}{9}$ =

$\frac{TC}{5}=\frac{50-32}{9}$

9(TC) = 5(50-32)

9TC = 5*18

TC = $\frac{90}{9}$

Tc = 10 °C

b) -40 °C → F

$\frac{TC}{5} = \frac{TF-32}{9}$

$\frac{-40}{5}=\frac{TF-32}{9}$

9(-40) = 5(TF-32)

-360 = 5(TF-32)

$\frac{-360}{5} = TF-32$

-72 = TF-32

-72+32 = TF

TF = 40 °F

c)393 K→ °C  

$\frac{TC}{5}=\frac{TK-273}{5}$

$\frac{TC}{5}= \frac{393-273}{5}$

TC = 120 °C

d)30 °C → K

$\frac{TC}{5}=\frac{TK-273}{5}$

$\frac{30}{5}= \frac{TK-273}{5}$

30 = TK-273

30+273 = TK

TK = 303 K

Explicação: