Question

URGENTE ME AJUDA !!!!!!
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Answer 1

Resposta:

04)

a)

$\sqrt{2} \times \sqrt{32} = \sqrt{2 \times 32} = \\ \\ \sqrt{64} = \green{8}$

b)

$\sqrt{48} \div \sqrt{12} = \\ \\ \sqrt{48 \div 12} = \\ \\ \sqrt{4} = \green{4}$

c)

$\sqrt[3]{2} \times \sqrt[3]{4} = \\ \\ \sqrt[3]{2 \times 4} \\ \\ \sqrt[3]{8} \\ \\ \green{2}$

d)

$\sqrt{50} \div \sqrt{2} = \\ \\ \sqrt{50 \div 2} \\ \\ \sqrt{25} \\ \\ \green{5}$

e)

$\sqrt{3} \times \sqrt{6} = \\ \\ \sqrt{3 \times 6} \\ \\ \sqrt{18} \\ \\ \sqrt{9 \times 2} \\ \\ \sqrt{9} \times \sqrt{2} \\ \\ \green{3 \sqrt{2} }$

f)

$\sqrt[4]{32} \div \sqrt[4]{2} = \\ \\ \sqrt[4]{32 \div 2} \\ \\ \sqrt[4]{16} \\ \\ \green{2}$

g)

$\dfrac{ \sqrt{3} \times \sqrt{8} }{ \sqrt{12} } = \\ \\ \dfrac{ \sqrt{3 \times 8} }{ \sqrt{12} } \\ \\ \dfrac{ \sqrt{24} }{ \sqrt{4 \times 3} } \\ \\ \dfrac{ \sqrt{4 \times 6} }{ \sqrt{4} \times \sqrt{3} } \\ \\ \dfrac{ \sqrt{4} \times \sqrt{6} }{2 \sqrt{3} } \\ \\ \dfrac{2 \sqrt{6} }{2 \sqrt{3} } \\ \\ \dfrac{ \sqrt{6} }{ \sqrt{3} } \times \dfrac{ \sqrt{3} }{ \sqrt{3} } \\ \\ \dfrac{ \sqrt{18} }{ \sqrt{9} } \\ \\ \dfrac{ \sqrt{9 \times 2} }{3} \\ \\ \dfrac{3 \sqrt{2} }{3} \\ \\ \green{\sqrt{2} }$

Bons Estudos!