Question

simplifique a expressão: 1+sen x / sec x +tag x

Answer 1

$sec(x)= \frac{1}{cos(x)}$

$tg(x)= \frac{sen(x)}{cos(x)}$

$sec(x)+tg(x)= \frac{1}{cos(x)} + \frac{sen(x)}{cos(x)}$

$\frac{1}{cos(x)} (1+sen(x))= sec(x) [1+sen(x)]=sec(x)+tg(x)$

Então
$\frac{1+sen(x)}{sec(x)+tg(x)} = \frac{1}{sec(x)}=cos(x)$