Question

1-Aplicando a fórmula de Bhaskara, resolva a equação do 2º grau.

 3x² – 7x + 4 = 0 r-3 e 4 .

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Answer 1

Resposta:

S={1, 4/3}

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~3x^{2}-7x+4=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=3{;}~b=-7~e~c=4\\\\C\'alculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-7)^{2}-4(3)(4)=49-(48)=1\\\\C\'alculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-7)-\sqrt{1}}{2(3)}=\frac{7-1}{6}=\frac{6}{6}=1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-7)+\sqrt{1}}{2(3)}=\frac{7+1}{6}=\frac{8\div2}{6\div2}=\frac{4}{3}$