Question

Me ajudem pfv !!

Resolva: x² + 8x + 16 < 0

Answer 1

x²+ 8x + 16 = 0
Δ= b² - 4xAxC
Δ= 8² - 4*1*16
Δ= 64-64
X= -b +- √Δ : 2A
X'= -8+0 :2 = -4
X"=-8 - 0 :2= -4